0.03x^2+0.06x-0.01=0

Solution for 0.03x^2+0.06x-0.01=0 equation:

0.03x^2+0.06x-0.01=0

a = 0.03; b = 0.06; c = -0.01;
Δ = b2-4ac
Δ = 0.062-4·0.03·(-0.01)
Δ = 0.0048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.0048}}{2*0.03}=\frac{-0.06-\sqrt{0.0048}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.0048}}{2*0.03}=\frac{-0.06+\sqrt{0.0048}}{0.06}
$